• Übungstest Nr. 5 - Lineare Funktionen
  • Christian Leeser
  • 30.06.2020
  • Mittlere Reife
  • Mathematik
  • 8
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Christian Leeser
1
Berechne zu den folgenden linearen Funktionen die Nullstelle.
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  • a) a(x)=4x+5,15\gdef\cloze#1{{\raisebox{-.05em}{\colorbox{none}{\color{526060}{\large{$\displaystyle #1$}}}}}} a(x) = 4x+5{,}15

  • b) b(x)=9,5x+33\gdef\cloze#1{{\raisebox{-.05em}{\colorbox{none}{\color{526060}{\large{$\displaystyle #1$}}}}}} b(x) =9{,}5x+33

  • c) c(x)=72x+5\gdef\cloze#1{{\raisebox{-.05em}{\colorbox{none}{\color{526060}{\large{$\displaystyle #1$}}}}}} c(x) =\frac{7}{2}x+5

  • d) d(x)=5x+11\gdef\cloze#1{{\raisebox{-.05em}{\colorbox{none}{\color{526060}{\large{$\displaystyle #1$}}}}}} d(x) =-5x+11
  • e) e(x)=112x+10,5\gdef\cloze#1{{\raisebox{-.05em}{\colorbox{none}{\color{526060}{\large{$\displaystyle #1$}}}}}} e(x) =-1 \frac{1}{2}x+10{,}5

  • f) f(x)=2x+0,5\gdef\cloze#1{{\raisebox{-.05em}{\colorbox{none}{\color{526060}{\large{$\displaystyle #1$}}}}}} f(x) =2x+0{,}5

  • g) g(x)=34x+15\gdef\cloze#1{{\raisebox{-.05em}{\colorbox{none}{\color{526060}{\large{$\displaystyle #1$}}}}}} g(x) =-\frac{3}{4}x+15

  • h) h(x)=204x+12\gdef\cloze#1{{\raisebox{-.05em}{\colorbox{none}{\color{526060}{\large{$\displaystyle #1$}}}}}} h(x) =\frac{20}{4}x+12
Lösung
a) (10380    0)\gdef\cloze#1{{\raisebox{-.05em}{\colorbox{none}{\color{526060}{\large{$\displaystyle #1$}}}}}} (-\frac{103}{80} \; | \; 0)

b) (6619    0)\gdef\cloze#1{{\raisebox{-.05em}{\colorbox{none}{\color{526060}{\large{$\displaystyle #1$}}}}}} (-\frac{66}{19} \; | \; 0)

c) (107    0)\gdef\cloze#1{{\raisebox{-.05em}{\colorbox{none}{\color{526060}{\large{$\displaystyle #1$}}}}}} (-\frac{10}{7} \; | \; 0)

d) (115    0)\gdef\cloze#1{{\raisebox{-.05em}{\colorbox{none}{\color{526060}{\large{$\displaystyle #1$}}}}}} (\frac{11}{5} \; | \; 0)

e) (7    0)\gdef\cloze#1{{\raisebox{-.05em}{\colorbox{none}{\color{526060}{\large{$\displaystyle #1$}}}}}} (7 \; | \; 0)

f) (14    0)\gdef\cloze#1{{\raisebox{-.05em}{\colorbox{none}{\color{526060}{\large{$\displaystyle #1$}}}}}} (-\frac{1}{4} \; | \; 0)

g) (20    0)\gdef\cloze#1{{\raisebox{-.05em}{\colorbox{none}{\color{526060}{\large{$\displaystyle #1$}}}}}} (20 \; | \; 0)

h) (125    0)\gdef\cloze#1{{\raisebox{-.05em}{\colorbox{none}{\color{526060}{\large{$\displaystyle #1$}}}}}} (-\frac{12}{5} \; | \; 0)
Note
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