• LK Nr. 4 - Brüche und Bruchrechnen
  • Christian Leeser
  • 30.06.2020
  • Mittlere Reife
  • Mathematik
  • 6
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Christian Leeser
1
Berechne die folgenden Brüche. Kürze das Ergebnis, wenn möglich.
8 / 8
  • 515+215\gdef\cloze#1{{\raisebox{-.05em}{\colorbox{none}{\color{526060}{\large{$\displaystyle #1$}}}}}} \frac{5}{15} +\frac{2}{15}

  • 26+26\gdef\cloze#1{{\raisebox{-.05em}{\colorbox{none}{\color{526060}{\large{$\displaystyle #1$}}}}}} \frac{2}{6} + \frac{2}{6}
  • 924+524\gdef\cloze#1{{\raisebox{-.05em}{\colorbox{none}{\color{526060}{\large{$\displaystyle #1$}}}}}} \frac{9}{24}+ \frac{5}{24}

  • 718+518\gdef\cloze#1{{\raisebox{-.05em}{\colorbox{none}{\color{526060}{\large{$\displaystyle #1$}}}}}} \frac{7}{18} + \frac{5}{18}
Lösung
a) 715\gdef\cloze#1{{\raisebox{-.05em}{\colorbox{none}{\color{526060}{\large{$\displaystyle #1$}}}}}} \frac{7}{15}
b) 46=23\gdef\cloze#1{{\raisebox{-.05em}{\colorbox{none}{\color{526060}{\large{$\displaystyle #1$}}}}}} \frac{4}{6} = \frac{2}{3}
c) 1424=712\gdef\cloze#1{{\raisebox{-.05em}{\colorbox{none}{\color{526060}{\large{$\displaystyle #1$}}}}}} \frac{14}{24} = \frac{7}{12}
d) 1218=23\gdef\cloze#1{{\raisebox{-.05em}{\colorbox{none}{\color{526060}{\large{$\displaystyle #1$}}}}}} \frac{12}{18} = \frac{2}{3}
2
Berechne die folgenden Brüche. Kürze das Ergebnis, wenn möglich.
8 / 8
  • 515215\gdef\cloze#1{{\raisebox{-.05em}{\colorbox{none}{\color{526060}{\large{$\displaystyle #1$}}}}}} \frac{5}{15} -\frac{2}{15}

  • 5616\gdef\cloze#1{{\raisebox{-.05em}{\colorbox{none}{\color{526060}{\large{$\displaystyle #1$}}}}}} \frac{5}{6} - \frac{1}{6}
  • 924524\gdef\cloze#1{{\raisebox{-.05em}{\colorbox{none}{\color{526060}{\large{$\displaystyle #1$}}}}}} \frac{9}{24}- \frac{5}{24}

  • 719519\gdef\cloze#1{{\raisebox{-.05em}{\colorbox{none}{\color{526060}{\large{$\displaystyle #1$}}}}}} \frac{7}{19} - \frac{5}{19}
Lösung
a) 315=15\gdef\cloze#1{{\raisebox{-.05em}{\colorbox{none}{\color{526060}{\large{$\displaystyle #1$}}}}}} \frac{3}{15} = \frac{1}{5}
b) 46=23\gdef\cloze#1{{\raisebox{-.05em}{\colorbox{none}{\color{526060}{\large{$\displaystyle #1$}}}}}} \frac{4}{6} = \frac{2}{3}
c) 424=16\gdef\cloze#1{{\raisebox{-.05em}{\colorbox{none}{\color{526060}{\large{$\displaystyle #1$}}}}}} \frac{4}{24} = \frac{1}{6}
d) 219\gdef\cloze#1{{\raisebox{-.05em}{\colorbox{none}{\color{526060}{\large{$\displaystyle #1$}}}}}} \frac{2}{19}
Lösung2
Berechne die folgenden Brüche. Kürze das Ergebnis, wenn möglich.
a) 315=15\gdef\cloze#1{{\raisebox{-.05em}{\colorbox{none}{\color{526060}{\large{$\displaystyle #1$}}}}}} \frac{3}{15} = \frac{1}{5}
b) 46=23\gdef\cloze#1{{\raisebox{-.05em}{\colorbox{none}{\color{526060}{\large{$\displaystyle #1$}}}}}} \frac{4}{6} = \frac{2}{3}
c) 424=16\gdef\cloze#1{{\raisebox{-.05em}{\colorbox{none}{\color{526060}{\large{$\displaystyle #1$}}}}}} \frac{4}{24} = \frac{1}{6}
d) 219\gdef\cloze#1{{\raisebox{-.05em}{\colorbox{none}{\color{526060}{\large{$\displaystyle #1$}}}}}} \frac{2}{19}
Christian Leeser
3
Berechne die folgenden Brüche. Kürze das Ergebnis, wenn möglich.
8 / 8
  • 310+15\gdef\cloze#1{{\raisebox{-.05em}{\colorbox{none}{\color{526060}{\large{$\displaystyle #1$}}}}}} \frac{3}{10} +\frac{1}{5}

  • 58+13\gdef\cloze#1{{\raisebox{-.05em}{\colorbox{none}{\color{526060}{\large{$\displaystyle #1$}}}}}} \frac{5}{8} + \frac{1}{3}
  • 1214\gdef\cloze#1{{\raisebox{-.05em}{\colorbox{none}{\color{526060}{\large{$\displaystyle #1$}}}}}} \frac{1}{2}- \frac{1}{4}

  • 5915\gdef\cloze#1{{\raisebox{-.05em}{\colorbox{none}{\color{526060}{\large{$\displaystyle #1$}}}}}} \frac{5}{9} - \frac{1}{5}
Lösung
a) 510=12\gdef\cloze#1{{\raisebox{-.05em}{\colorbox{none}{\color{526060}{\large{$\displaystyle #1$}}}}}} \frac{5}{10} = \frac{1}{2}
b) 2324\gdef\cloze#1{{\raisebox{-.05em}{\colorbox{none}{\color{526060}{\large{$\displaystyle #1$}}}}}} \frac{23}{24}
c) 14\gdef\cloze#1{{\raisebox{-.05em}{\colorbox{none}{\color{526060}{\large{$\displaystyle #1$}}}}}} \frac{1}{4}
d) 1645\gdef\cloze#1{{\raisebox{-.05em}{\colorbox{none}{\color{526060}{\large{$\displaystyle #1$}}}}}} \frac{16}{45}
Note
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