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  • Bruchgleichungen (einfach-mittel)
  • anonym
  • 19.11.2020
  • Mathematik
  • 8
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Name:
Bruchgleichungen (einfach-mittel)
17.11.2020
1
★ Berechne die unbekannte Variable.
  • x2=6x=12\gdef\cloze#1{{\raisebox{-.05em}{\colorbox{none}{\color{transparent}{\large{$\displaystyle #1$}}}}}} \quad \quad \begin{aligned} \frac{x}{2}&=6 \\ x&=\cloze{12} \end{aligned}
  • x4=5x=20\gdef\cloze#1{{\raisebox{-.05em}{\colorbox{none}{\color{transparent}{\large{$\displaystyle #1$}}}}}} \quad \quad \begin{aligned} \frac{x}{4}&=5 \\ x&=\cloze{20} \end{aligned}
  • x3=10x=30\gdef\cloze#1{{\raisebox{-.05em}{\colorbox{none}{\color{transparent}{\large{$\displaystyle #1$}}}}}} \quad \quad \begin{aligned} \frac{x}{3}&=10 \\ x&=\cloze{30} \end{aligned}
  • x6=1x=6\gdef\cloze#1{{\raisebox{-.05em}{\colorbox{none}{\color{transparent}{\large{$\displaystyle #1$}}}}}} \quad \quad \begin{aligned} \frac{x}{6}&=1 \\ x&=\cloze{6} \end{aligned}
2
★ Berechne die unbekannte Variable.
  • 10⋅x3−9=1x=3\gdef\cloze#1{{\raisebox{-.05em}{\colorbox{none}{\color{transparent}{\large{$\displaystyle #1$}}}}}} \quad \quad \begin{aligned} \frac{10 \cdot x}{3}-9&=1 \\ x&=\cloze{3} \end{aligned}
  • 11⋅x2−14=−3x=2\gdef\cloze#1{{\raisebox{-.05em}{\colorbox{none}{\color{transparent}{\large{$\displaystyle #1$}}}}}} \quad \quad \begin{aligned} \frac{11 \cdot x}{2}-14&=-3 \\ x&=\cloze{2} \end{aligned}
  • 7⋅x2+3=10x=2\gdef\cloze#1{{\raisebox{-.05em}{\colorbox{none}{\color{transparent}{\large{$\displaystyle #1$}}}}}} \quad \quad \begin{aligned} \frac{7 \cdot x}{2}+3&=10 \\ x&=\cloze{2} \end{aligned}
  • 4⋅x4−17=−15x=2\gdef\cloze#1{{\raisebox{-.05em}{\colorbox{none}{\color{transparent}{\large{$\displaystyle #1$}}}}}} \quad \quad \begin{aligned} \frac{4 \cdot x}{4}-17&=-15 \\ x&=\cloze{2} \end{aligned}
3
★ Berechne die unbekannte Variable.
  • 6x63=163x=56\gdef\cloze#1{{\raisebox{-.05em}{\colorbox{none}{\color{transparent}{\large{$\displaystyle #1$}}}}}} \quad \quad \begin{aligned} \frac{6 x}{63}&=\frac{16}{3} \\ x&=\cloze{56} \end{aligned}
  • 5x28=307x=24\gdef\cloze#1{{\raisebox{-.05em}{\colorbox{none}{\color{transparent}{\large{$\displaystyle #1$}}}}}} \quad \quad \begin{aligned} \frac{5 x}{28}&=\frac{30}{7} \\ x&=\cloze{24} \end{aligned}
  • 2x24=43x=16\gdef\cloze#1{{\raisebox{-.05em}{\colorbox{none}{\color{transparent}{\large{$\displaystyle #1$}}}}}} \quad \quad \begin{aligned} \frac{2 x}{24}&=\frac{4}{3} \\ x&=\cloze{16} \end{aligned}
  • 5x16=254x=20\gdef\cloze#1{{\raisebox{-.05em}{\colorbox{none}{\color{transparent}{\large{$\displaystyle #1$}}}}}} \quad \quad \begin{aligned} \frac{5 x}{16}&=\frac{25}{4} \\ x&=\cloze{20} \end{aligned}
4
★★ Berechne die unbekannte Variable.
  • 7(x+47=4(74+x)x=0.5\gdef\cloze#1{{\raisebox{-.05em}{\colorbox{none}{\color{transparent}{\large{$\displaystyle #1$}}}}}} \quad \quad \begin{aligned} 7(x+\frac{4}{7}&=4(\frac{7}{4}+x) \\ x&=\cloze{0.5} \end{aligned}
  • 9(x+78)=9(x−94)x=−29\gdef\cloze#1{{\raisebox{-.05em}{\colorbox{none}{\color{transparent}{\large{$\displaystyle #1$}}}}}} \quad \quad \begin{aligned} 9(x+\frac{7}{8})&=9(x-\frac{9}{4})\\ x&=\cloze{-29} \end{aligned}
  • −7x4+3=−3x14+3x=0\gdef\cloze#1{{\raisebox{-.05em}{\colorbox{none}{\color{transparent}{\large{$\displaystyle #1$}}}}}} \quad \quad \begin{aligned} -\frac{7x}{4}+3&=-\frac{3x}{14}+3\\ x&=\cloze{0} \end{aligned}
  • 32=7−x8x=−5\gdef\cloze#1{{\raisebox{-.05em}{\colorbox{none}{\color{transparent}{\large{$\displaystyle #1$}}}}}} \quad \quad \begin{aligned} \frac{3}{2}&=\frac{7-x}{8}\\ x&=\cloze{-5} \end{aligned}
  • 9x−811=4x5x=40\gdef\cloze#1{{\raisebox{-.05em}{\colorbox{none}{\color{transparent}{\large{$\displaystyle #1$}}}}}} \quad \quad \begin{aligned} \frac{9x-8}{11}&=\frac{4x}{5}\\ x&=\cloze{40} \end{aligned}
  • 2x−65=6+5x11x=−33\gdef\cloze#1{{\raisebox{-.05em}{\colorbox{none}{\color{transparent}{\large{$\displaystyle #1$}}}}}} \quad \quad \begin{aligned} \frac{2x-6}{5}&=\frac{6+5x}{11}\\ x&=\cloze{-33} \end{aligned}
Mathematik
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