• UeT Nr. 4: Winkel benennen und erkennen
  • Christian Leeser
  • 19.08.2021
  • Mittlere Reife
  • Mathematik
  • 6
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1
Fülle die Lücken mit den richtigen Begriffen.
  • S =
  • α=\gdef\cloze#1{{\raisebox{-.05em}{\colorbox{none}{\color{transparent}{\large{$\displaystyle #1$}}}}}} \alpha =
  • a =
  • b =
baS
2
Benenne die griechischen Buchstaben
  • α\gdef\cloze#1{{\raisebox{-.05em}{\colorbox{none}{\color{transparent}{\large{$\displaystyle #1$}}}}}} \alpha =
  • β\gdef\cloze#1{{\raisebox{-.05em}{\colorbox{none}{\color{transparent}{\large{$\displaystyle #1$}}}}}} \beta =
  • γ\gdef\cloze#1{{\raisebox{-.05em}{\colorbox{none}{\color{transparent}{\large{$\displaystyle #1$}}}}}} \gamma =
  • δ\gdef\cloze#1{{\raisebox{-.05em}{\colorbox{none}{\color{transparent}{\large{$\displaystyle #1$}}}}}} \delta =
  • ϵ\gdef\cloze#1{{\raisebox{-.05em}{\colorbox{none}{\color{transparent}{\large{$\displaystyle #1$}}}}}} \epsilon =
  • ϕ\gdef\cloze#1{{\raisebox{-.05em}{\colorbox{none}{\color{transparent}{\large{$\displaystyle #1$}}}}}} \phi =
3
Benennen zu den Angaben die passende Winkelart.
  • 0α<90\gdef\cloze#1{{\raisebox{-.05em}{\colorbox{none}{\color{transparent}{\large{$\displaystyle #1$}}}}}} 0^\circ \le \alpha < 90^\circ
  • α=90\gdef\cloze#1{{\raisebox{-.05em}{\colorbox{none}{\color{transparent}{\large{$\displaystyle #1$}}}}}} \alpha = 90^\circ
  • 90<α<180\gdef\cloze#1{{\raisebox{-.05em}{\colorbox{none}{\color{transparent}{\large{$\displaystyle #1$}}}}}} 90^\circ < \alpha < 180^\circ
  • α=180\gdef\cloze#1{{\raisebox{-.05em}{\colorbox{none}{\color{transparent}{\large{$\displaystyle #1$}}}}}} \alpha = 180^\circ
  • 180<α<360\gdef\cloze#1{{\raisebox{-.05em}{\colorbox{none}{\color{transparent}{\large{$\displaystyle #1$}}}}}} 180^\circ < \alpha < 360^\circ
  • α=360\gdef\cloze#1{{\raisebox{-.05em}{\colorbox{none}{\color{transparent}{\large{$\displaystyle #1$}}}}}} \alpha = 360^\circ
x