• UeT Nr. 5 - Quadratische Gleichungen lösen
  • Christian Leeser
  • 07.03.2023
  • Mathematik
  • 8, 9, 10
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1
Be­stim­me die Lö­sungs­men­ge der fol­gen­den qua­dra­ti­schen Glei­chun­gen.
  • 8x2+16=0\gdef\cloze#1{{\raisebox{-.05em}{\colorbox{none}{\color{transparent}{\large{$\displaystyle #1$}}}}}} 8x^{2}+16=0
  • 3x2100=525\gdef\cloze#1{{\raisebox{-.05em}{\colorbox{none}{\color{transparent}{\large{$\displaystyle #1$}}}}}} 3x^{2}-100=525
  • x2=1\gdef\cloze#1{{\raisebox{-.05em}{\colorbox{none}{\color{transparent}{\large{$\displaystyle #1$}}}}}} x^{2}=1
  • x2=0\gdef\cloze#1{{\raisebox{-.05em}{\colorbox{none}{\color{transparent}{\large{$\displaystyle #1$}}}}}} x^{2}=0
  • x2=116\gdef\cloze#1{{\raisebox{-.05em}{\colorbox{none}{\color{transparent}{\large{$\displaystyle #1$}}}}}} x^{2}=\frac{1}{16}
  • 5x2245=0\gdef\cloze#1{{\raisebox{-.05em}{\colorbox{none}{\color{transparent}{\large{$\displaystyle #1$}}}}}} 5x^{2}-245=0
  • x2=36289\gdef\cloze#1{{\raisebox{-.05em}{\colorbox{none}{\color{transparent}{\large{$\displaystyle #1$}}}}}} x^{2}=\frac{36}{289}
  • x2=0,01\gdef\cloze#1{{\raisebox{-.05em}{\colorbox{none}{\color{transparent}{\large{$\displaystyle #1$}}}}}} x^{2}=-0{,}01
  • 2x2=98\gdef\cloze#1{{\raisebox{-.05em}{\colorbox{none}{\color{transparent}{\large{$\displaystyle #1$}}}}}} 2x^{2}=98
  • 13x2=3\gdef\cloze#1{{\raisebox{-.05em}{\colorbox{none}{\color{transparent}{\large{$\displaystyle #1$}}}}}} \frac{1}{3}x^{2}=3
  • 4x2100=156\gdef\cloze#1{{\raisebox{-.05em}{\colorbox{none}{\color{transparent}{\large{$\displaystyle #1$}}}}}} 4x^{2}-100=156
  • 5x2+80=0\gdef\cloze#1{{\raisebox{-.05em}{\colorbox{none}{\color{transparent}{\large{$\displaystyle #1$}}}}}} 5x^{2}+80=0
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