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  • 06.10.2020
  • Mathematik
  • 5, 6
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Name:
Rechengesetze
13.06.2020

Punkt vor Strich

1
Berechne!
  • 4⋅9+8=44\gdef\cloze#1{{\raisebox{-.05em}{\colorbox{none}{\color{transparent}{\large{$\displaystyle #1$}}}}}} 4 \cdot 9 + 8 = \cloze{44}
  • 4⋅7+9=37\gdef\cloze#1{{\raisebox{-.05em}{\colorbox{none}{\color{transparent}{\large{$\displaystyle #1$}}}}}} 4 \cdot 7 + 9 = \cloze{37}
  • 3+9⋅10=93\gdef\cloze#1{{\raisebox{-.05em}{\colorbox{none}{\color{transparent}{\large{$\displaystyle #1$}}}}}} 3 + 9 \cdot 10 = \cloze{93}
  • 7⋅4+6=34\gdef\cloze#1{{\raisebox{-.05em}{\colorbox{none}{\color{transparent}{\large{$\displaystyle #1$}}}}}} 7 \cdot 4 + 6 = \cloze{34}
  • 7+5⋅6=37\gdef\cloze#1{{\raisebox{-.05em}{\colorbox{none}{\color{transparent}{\large{$\displaystyle #1$}}}}}} 7 + 5 \cdot 6 = \cloze{37}
  • 10⋅5+9⋅5=95\gdef\cloze#1{{\raisebox{-.05em}{\colorbox{none}{\color{transparent}{\large{$\displaystyle #1$}}}}}} 10 \cdot 5 + 9 \cdot 5 = \cloze{95}

a+b⋅ca⋅b+ca⋅b+c⋅d\gdef\cloze#1{{\raisebox{-.05em}{\colorbox{none}{\color{transparent}{\large{$\displaystyle #1$}}}}}} a + b \cdot c \\ a \cdot b + c \\ a \cdot b + c \cdot d

2
Berechne!
  • 4⋅14+9⋅18=218\gdef\cloze#1{{\raisebox{-.05em}{\colorbox{none}{\color{transparent}{\large{$\displaystyle #1$}}}}}} 4 \cdot 14 + 9 \cdot 18 = \cloze{218}
  • 4+12⋅9=112\gdef\cloze#1{{\raisebox{-.05em}{\colorbox{none}{\color{transparent}{\large{$\displaystyle #1$}}}}}} 4 + 12 \cdot 9 = \cloze{112}
  • 7⋅17+5⋅14=189\gdef\cloze#1{{\raisebox{-.05em}{\colorbox{none}{\color{transparent}{\large{$\displaystyle #1$}}}}}} 7 \cdot 17 + 5 \cdot 14 = \cloze{189}
  • 3⋅14+3=45\gdef\cloze#1{{\raisebox{-.05em}{\colorbox{none}{\color{transparent}{\large{$\displaystyle #1$}}}}}} 3 \cdot 14 + 3 = \cloze{45}
  • 4⋅12+6⋅12=120\gdef\cloze#1{{\raisebox{-.05em}{\colorbox{none}{\color{transparent}{\large{$\displaystyle #1$}}}}}} 4 \cdot 12 + 6 \cdot 12 = \cloze{120}
  • 8+18⋅6=116\gdef\cloze#1{{\raisebox{-.05em}{\colorbox{none}{\color{transparent}{\large{$\displaystyle #1$}}}}}} 8 + 18 \cdot 6 = \cloze{116}
  • 5+14⋅8=117\gdef\cloze#1{{\raisebox{-.05em}{\colorbox{none}{\color{transparent}{\large{$\displaystyle #1$}}}}}} 5 + 14 \cdot 8 = \cloze{117}
  • 8⋅14+4⋅15=172\gdef\cloze#1{{\raisebox{-.05em}{\colorbox{none}{\color{transparent}{\large{$\displaystyle #1$}}}}}} 8 \cdot 14 + 4 \cdot 15 = \cloze{172}

Erhöhter Schwierigkeitsgrad durch erweiterte Zahlenbereiche

3
Berechne!
  • 8−6⋅4=−16\gdef\cloze#1{{\raisebox{-.05em}{\colorbox{none}{\color{transparent}{\large{$\displaystyle #1$}}}}}} 8 - 6 \cdot 4 = \cloze{-16}
  • 7⋅8−10⋅3=26\gdef\cloze#1{{\raisebox{-.05em}{\colorbox{none}{\color{transparent}{\large{$\displaystyle #1$}}}}}} 7 \cdot 8 - 10 \cdot 3 = \cloze{26}
  • 7−2⋅9=−11\gdef\cloze#1{{\raisebox{-.05em}{\colorbox{none}{\color{transparent}{\large{$\displaystyle #1$}}}}}} 7 - 2 \cdot 9 = \cloze{-11}
  • 8⋅5−4=36\gdef\cloze#1{{\raisebox{-.05em}{\colorbox{none}{\color{transparent}{\large{$\displaystyle #1$}}}}}} 8 \cdot 5 - 4 = \cloze{36}
  • 3−9⋅8=−69\gdef\cloze#1{{\raisebox{-.05em}{\colorbox{none}{\color{transparent}{\large{$\displaystyle #1$}}}}}} 3 - 9 \cdot 8 = \cloze{-69}
  • 7−8⋅3=−17\gdef\cloze#1{{\raisebox{-.05em}{\colorbox{none}{\color{transparent}{\large{$\displaystyle #1$}}}}}} 7 - 8 \cdot 3 = \cloze{-17}

a−b⋅ca⋅b−ca⋅b−c⋅d\gdef\cloze#1{{\raisebox{-.05em}{\colorbox{none}{\color{transparent}{\large{$\displaystyle #1$}}}}}} a - b \cdot c \\ a \cdot b - c \\ a \cdot b - c \cdot d

4
Berechne!
  • 7−14⋅9=−119\gdef\cloze#1{{\raisebox{-.05em}{\colorbox{none}{\color{transparent}{\large{$\displaystyle #1$}}}}}} 7 - 14 \cdot 9 = \cloze{-119}
  • 5⋅17−4=81\gdef\cloze#1{{\raisebox{-.05em}{\colorbox{none}{\color{transparent}{\large{$\displaystyle #1$}}}}}} 5 \cdot 17 - 4 = \cloze{81}
  • 6⋅15−2⋅16=58\gdef\cloze#1{{\raisebox{-.05em}{\colorbox{none}{\color{transparent}{\large{$\displaystyle #1$}}}}}} 6 \cdot 15 - 2 \cdot 16 = \cloze{58}
  • 3⋅17−10⋅19=−139\gdef\cloze#1{{\raisebox{-.05em}{\colorbox{none}{\color{transparent}{\large{$\displaystyle #1$}}}}}} 3 \cdot 17 - 10 \cdot 19 = \cloze{-139}
  • 8⋅16−8⋅13=24\gdef\cloze#1{{\raisebox{-.05em}{\colorbox{none}{\color{transparent}{\large{$\displaystyle #1$}}}}}} 8 \cdot 16 - 8 \cdot 13 = \cloze{24}
  • 3⋅18−2⋅13=28\gdef\cloze#1{{\raisebox{-.05em}{\colorbox{none}{\color{transparent}{\large{$\displaystyle #1$}}}}}} 3 \cdot 18 - 2 \cdot 13 = \cloze{28}
  • 7−18⋅6=−101\gdef\cloze#1{{\raisebox{-.05em}{\colorbox{none}{\color{transparent}{\large{$\displaystyle #1$}}}}}} 7 - 18 \cdot 6 = \cloze{-101}
  • 3⋅17−5⋅19=−44\gdef\cloze#1{{\raisebox{-.05em}{\colorbox{none}{\color{transparent}{\large{$\displaystyle #1$}}}}}} 3 \cdot 17 - 5 \cdot 19 = \cloze{-44}
5
Berechne!
  • 3⋅16−2⋅10=28\gdef\cloze#1{{\raisebox{-.05em}{\colorbox{none}{\color{transparent}{\large{$\displaystyle #1$}}}}}} 3 \cdot 16 - 2 \cdot 10 = \cloze{28}
  • 5−14⋅4=−51\gdef\cloze#1{{\raisebox{-.05em}{\colorbox{none}{\color{transparent}{\large{$\displaystyle #1$}}}}}} 5 - 14 \cdot 4 = \cloze{-51}
  • 9⋅6+7=61\gdef\cloze#1{{\raisebox{-.05em}{\colorbox{none}{\color{transparent}{\large{$\displaystyle #1$}}}}}} 9 \cdot 6 + 7 = \cloze{61}
  • 4−14⋅8=−108\gdef\cloze#1{{\raisebox{-.05em}{\colorbox{none}{\color{transparent}{\large{$\displaystyle #1$}}}}}} 4 - 14 \cdot 8 = \cloze{-108}
  • 10−11⋅4=−34\gdef\cloze#1{{\raisebox{-.05em}{\colorbox{none}{\color{transparent}{\large{$\displaystyle #1$}}}}}} 10 - 11 \cdot 4 = \cloze{-34}
  • 5⋅10−6=44\gdef\cloze#1{{\raisebox{-.05em}{\colorbox{none}{\color{transparent}{\large{$\displaystyle #1$}}}}}} 5 \cdot 10 - 6 = \cloze{44}
  • 7+5⋅7=42\gdef\cloze#1{{\raisebox{-.05em}{\colorbox{none}{\color{transparent}{\large{$\displaystyle #1$}}}}}} 7 + 5 \cdot 7 = \cloze{42}
  • 5+9⋅7=68\gdef\cloze#1{{\raisebox{-.05em}{\colorbox{none}{\color{transparent}{\large{$\displaystyle #1$}}}}}} 5 + 9 \cdot 7 = \cloze{68}
  • 2−11⋅5=−53\gdef\cloze#1{{\raisebox{-.05em}{\colorbox{none}{\color{transparent}{\large{$\displaystyle #1$}}}}}} 2 - 11 \cdot 5 = \cloze{-53}
  • 7⋅13−2⋅9=73\gdef\cloze#1{{\raisebox{-.05em}{\colorbox{none}{\color{transparent}{\large{$\displaystyle #1$}}}}}} 7 \cdot 13 - 2 \cdot 9 = \cloze{73}
  • 8−19⋅2=−30\gdef\cloze#1{{\raisebox{-.05em}{\colorbox{none}{\color{transparent}{\large{$\displaystyle #1$}}}}}} 8 - 19 \cdot 2 = \cloze{-30}
  • 3⋅13+10⋅7=109\gdef\cloze#1{{\raisebox{-.05em}{\colorbox{none}{\color{transparent}{\large{$\displaystyle #1$}}}}}} 3 \cdot 13 + 10 \cdot 7 = \cloze{109}

Mischung der Aufgaben

1-4

Mathematik
Seite 1/3
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Name:
Rechengesetze
13.06.2020

Klammern zuerst

1
Berechne!
  • (4+7)⋅8=88\gdef\cloze#1{{\raisebox{-.05em}{\colorbox{none}{\color{transparent}{\large{$\displaystyle #1$}}}}}} (4 + 7) \cdot 8 = \cloze{88}
  • (4+8)⋅(2+2)=48\gdef\cloze#1{{\raisebox{-.05em}{\colorbox{none}{\color{transparent}{\large{$\displaystyle #1$}}}}}} (4 + 8) \cdot (2 + 2) = \cloze{48}
  • 7⋅(7+7)=98\gdef\cloze#1{{\raisebox{-.05em}{\colorbox{none}{\color{transparent}{\large{$\displaystyle #1$}}}}}} 7 \cdot (7 + 7) = \cloze{98}
  • (3+3)⋅5=30\gdef\cloze#1{{\raisebox{-.05em}{\colorbox{none}{\color{transparent}{\large{$\displaystyle #1$}}}}}} (3 + 3) \cdot 5 = \cloze{30}

a⋅(b+c)(a+b)⋅c(a+b)⋅(c+d)\gdef\cloze#1{{\raisebox{-.05em}{\colorbox{none}{\color{transparent}{\large{$\displaystyle #1$}}}}}} a \cdot (b+c) \\ (a+b) \cdot c \\ (a+b) \cdot (c+d)

2
Berechne!
  • (7−7)⋅13=0\gdef\cloze#1{{\raisebox{-.05em}{\colorbox{none}{\color{transparent}{\large{$\displaystyle #1$}}}}}} (7 - 7) \cdot 13 = \cloze{0}
  • (13−4)⋅(4−3)=9\gdef\cloze#1{{\raisebox{-.05em}{\colorbox{none}{\color{transparent}{\large{$\displaystyle #1$}}}}}} (13 - 4) \cdot (4 - 3) = \cloze{9}
  • 8⋅(3−11)=−64\gdef\cloze#1{{\raisebox{-.05em}{\colorbox{none}{\color{transparent}{\large{$\displaystyle #1$}}}}}} 8 \cdot (3 - 11) = \cloze{-64}
  • 4⋅(12−10)=8\gdef\cloze#1{{\raisebox{-.05em}{\colorbox{none}{\color{transparent}{\large{$\displaystyle #1$}}}}}} 4 \cdot (12 - 10) = \cloze{8}

a⋅(b−c)(a−b)⋅c(a−b)⋅(c−d)\gdef\cloze#1{{\raisebox{-.05em}{\colorbox{none}{\color{transparent}{\large{$\displaystyle #1$}}}}}} a \cdot (b-c) \\ (a-b) \cdot c \\ (a-b) \cdot (c-d)

3
Berechne!
  • (7+3)⋅(15−1)=140\gdef\cloze#1{{\raisebox{-.05em}{\colorbox{none}{\color{transparent}{\large{$\displaystyle #1$}}}}}} (7 + 3) \cdot (15 - 1) = \cloze{140}
  • (12−1)⋅(11−9)=22\gdef\cloze#1{{\raisebox{-.05em}{\colorbox{none}{\color{transparent}{\large{$\displaystyle #1$}}}}}} (12 - 1) \cdot (11 - 9) = \cloze{22}
  • (9−2)⋅(14−4)=70\gdef\cloze#1{{\raisebox{-.05em}{\colorbox{none}{\color{transparent}{\large{$\displaystyle #1$}}}}}} (9 - 2) \cdot (14 - 4) = \cloze{70}
  • (3−6)⋅(12+4)=−48\gdef\cloze#1{{\raisebox{-.05em}{\colorbox{none}{\color{transparent}{\large{$\displaystyle #1$}}}}}} (3 - 6) \cdot (12 + 4) = \cloze{-48}

"Klammer mal Klammer" in vier möglichen Varianten

4
Berechne!
  • 2+7⋅(7+3)=72\gdef\cloze#1{{\raisebox{-.05em}{\colorbox{none}{\color{transparent}{\large{$\displaystyle #1$}}}}}} 2 + 7 \cdot (7 + 3) = \cloze{72}
  • 4⋅(6+1)+5=33\gdef\cloze#1{{\raisebox{-.05em}{\colorbox{none}{\color{transparent}{\large{$\displaystyle #1$}}}}}} 4 \cdot (6 + 1) + 5 = \cloze{33}
  • 4+(4+4)⋅4=36\gdef\cloze#1{{\raisebox{-.05em}{\colorbox{none}{\color{transparent}{\large{$\displaystyle #1$}}}}}} 4 + (4 + 4) \cdot 4 = \cloze{36}
  • 8+9⋅(3+10)=125\gdef\cloze#1{{\raisebox{-.05em}{\colorbox{none}{\color{transparent}{\large{$\displaystyle #1$}}}}}} 8 + 9 \cdot (3 + 10) = \cloze{125}

(a+b)⋅c+d\gdef\cloze#1{{\raisebox{-.05em}{\colorbox{none}{\color{transparent}{\large{$\displaystyle #1$}}}}}} (a+b) \cdot c +d

in vier verschiedenen Anordnungen

5
Berechne!
  • 4+1⋅(5−9)=0\gdef\cloze#1{{\raisebox{-.05em}{\colorbox{none}{\color{transparent}{\large{$\displaystyle #1$}}}}}} 4 + 1 \cdot (5 - 9) = \cloze{0}
  • 6⋅(8−2)+3=39\gdef\cloze#1{{\raisebox{-.05em}{\colorbox{none}{\color{transparent}{\large{$\displaystyle #1$}}}}}} 6 \cdot (8 - 2) + 3 = \cloze{39}
  • (10−3)⋅8+5=61\gdef\cloze#1{{\raisebox{-.05em}{\colorbox{none}{\color{transparent}{\large{$\displaystyle #1$}}}}}} (10 - 3) \cdot 8 + 5 = \cloze{61}
  • 4+9⋅(4−5)=−5\gdef\cloze#1{{\raisebox{-.05em}{\colorbox{none}{\color{transparent}{\large{$\displaystyle #1$}}}}}} 4 + 9 \cdot (4 - 5) = \cloze{-5}

(a−b)⋅c+d\gdef\cloze#1{{\raisebox{-.05em}{\colorbox{none}{\color{transparent}{\large{$\displaystyle #1$}}}}}} (a-b) \cdot c +d

in vier verschiedenen Anordnungen

Mathematik
Seite 2/3
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Name:
Rechengesetze
13.06.2020
6
Berechne!
  • (7+4)⋅4−7=37\gdef\cloze#1{{\raisebox{-.05em}{\colorbox{none}{\color{transparent}{\large{$\displaystyle #1$}}}}}} (7 + 4) \cdot 4 - 7 = \cloze{37}
  • 2−2⋅(3+2)=−8\gdef\cloze#1{{\raisebox{-.05em}{\colorbox{none}{\color{transparent}{\large{$\displaystyle #1$}}}}}} 2 - 2 \cdot (3 + 2) = \cloze{-8}
  • (6+7)⋅4−4=48\gdef\cloze#1{{\raisebox{-.05em}{\colorbox{none}{\color{transparent}{\large{$\displaystyle #1$}}}}}} (6 + 7) \cdot 4 - 4 = \cloze{48}
  • 2⋅(5+3)−2=14\gdef\cloze#1{{\raisebox{-.05em}{\colorbox{none}{\color{transparent}{\large{$\displaystyle #1$}}}}}} 2 \cdot (5 + 3) - 2 = \cloze{14}

(a+b)⋅c−dbzw.d−(a+b)⋅c\gdef\cloze#1{{\raisebox{-.05em}{\colorbox{none}{\color{transparent}{\large{$\displaystyle #1$}}}}}} (a+b) \cdot c - d \\ \text{bzw.} \\ d - (a+b) \cdot c

7
Berechne!
  • 3−3⋅(7−4)=−6\gdef\cloze#1{{\raisebox{-.05em}{\colorbox{none}{\color{transparent}{\large{$\displaystyle #1$}}}}}} 3 - 3 \cdot (7 - 4) = \cloze{-6}
  • 5−10⋅(6−5)=−5\gdef\cloze#1{{\raisebox{-.05em}{\colorbox{none}{\color{transparent}{\large{$\displaystyle #1$}}}}}} 5 - 10 \cdot (6 - 5) = \cloze{-5}
  • (4−5)⋅4−6=−10\gdef\cloze#1{{\raisebox{-.05em}{\colorbox{none}{\color{transparent}{\large{$\displaystyle #1$}}}}}} (4 - 5) \cdot 4 - 6 = \cloze{-10}
  • 5−(3−8)⋅8=45\gdef\cloze#1{{\raisebox{-.05em}{\colorbox{none}{\color{transparent}{\large{$\displaystyle #1$}}}}}} 5 - (3 - 8) \cdot 8 = \cloze{45}

(a−b)⋅c−dbzw.d−(a−b)⋅c\gdef\cloze#1{{\raisebox{-.05em}{\colorbox{none}{\color{transparent}{\large{$\displaystyle #1$}}}}}} (a-b) \cdot c - d \\ \text{bzw.} \\ d - (a-b) \cdot c

Es sind natürlich noch zahlreiche weitere Varianten dieser Aufgaben möglich - der Kreativität sind hier keine Grenzen gesetzt!

Mathematik
Seite 3/3
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