• Rechengesetze
  • ttry-Katalog
  • 06.10.2020
  • Mathematik
  • 5, 6
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  • Punkt vor Strich

    1
    Berechne!
    • 49+8=44\gdef\cloze#1{\colorbox{none}{\color{transparent}{\large{$\displaystyle #1$}}}} 4 \cdot 9 + 8 = \cloze{44}
    • 47+9=37\gdef\cloze#1{\colorbox{none}{\color{transparent}{\large{$\displaystyle #1$}}}} 4 \cdot 7 + 9 = \cloze{37}
    • 3+910=93\gdef\cloze#1{\colorbox{none}{\color{transparent}{\large{$\displaystyle #1$}}}} 3 + 9 \cdot 10 = \cloze{93}
    • 74+6=34\gdef\cloze#1{\colorbox{none}{\color{transparent}{\large{$\displaystyle #1$}}}} 7 \cdot 4 + 6 = \cloze{34}
    • 7+56=37\gdef\cloze#1{\colorbox{none}{\color{transparent}{\large{$\displaystyle #1$}}}} 7 + 5 \cdot 6 = \cloze{37}
    • 105+95=95\gdef\cloze#1{\colorbox{none}{\color{transparent}{\large{$\displaystyle #1$}}}} 10 \cdot 5 + 9 \cdot 5 = \cloze{95}

    a+bcab+cab+cd\gdef\cloze#1{\colorbox{none}{\color{transparent}{\large{$\displaystyle #1$}}}} a + b \cdot c \\ a \cdot b + c \\ a \cdot b + c \cdot d

    2
    Berechne!
    • 414+918=218\gdef\cloze#1{\colorbox{none}{\color{transparent}{\large{$\displaystyle #1$}}}} 4 \cdot 14 + 9 \cdot 18 = \cloze{218}
    • 4+129=112\gdef\cloze#1{\colorbox{none}{\color{transparent}{\large{$\displaystyle #1$}}}} 4 + 12 \cdot 9 = \cloze{112}
    • 717+514=189\gdef\cloze#1{\colorbox{none}{\color{transparent}{\large{$\displaystyle #1$}}}} 7 \cdot 17 + 5 \cdot 14 = \cloze{189}
    • 314+3=45\gdef\cloze#1{\colorbox{none}{\color{transparent}{\large{$\displaystyle #1$}}}} 3 \cdot 14 + 3 = \cloze{45}
    • 412+612=120\gdef\cloze#1{\colorbox{none}{\color{transparent}{\large{$\displaystyle #1$}}}} 4 \cdot 12 + 6 \cdot 12 = \cloze{120}
    • 8+186=116\gdef\cloze#1{\colorbox{none}{\color{transparent}{\large{$\displaystyle #1$}}}} 8 + 18 \cdot 6 = \cloze{116}
    • 5+148=117\gdef\cloze#1{\colorbox{none}{\color{transparent}{\large{$\displaystyle #1$}}}} 5 + 14 \cdot 8 = \cloze{117}
    • 814+415=172\gdef\cloze#1{\colorbox{none}{\color{transparent}{\large{$\displaystyle #1$}}}} 8 \cdot 14 + 4 \cdot 15 = \cloze{172}

    Erhöhter Schwierigkeitsgrad durch erweiterte Zahlenbereiche

    3
    Berechne!
    • 864=16\gdef\cloze#1{\colorbox{none}{\color{transparent}{\large{$\displaystyle #1$}}}} 8 - 6 \cdot 4 = \cloze{-16}
    • 78103=26\gdef\cloze#1{\colorbox{none}{\color{transparent}{\large{$\displaystyle #1$}}}} 7 \cdot 8 - 10 \cdot 3 = \cloze{26}
    • 729=11\gdef\cloze#1{\colorbox{none}{\color{transparent}{\large{$\displaystyle #1$}}}} 7 - 2 \cdot 9 = \cloze{-11}
    • 854=36\gdef\cloze#1{\colorbox{none}{\color{transparent}{\large{$\displaystyle #1$}}}} 8 \cdot 5 - 4 = \cloze{36}
    • 398=69\gdef\cloze#1{\colorbox{none}{\color{transparent}{\large{$\displaystyle #1$}}}} 3 - 9 \cdot 8 = \cloze{-69}
    • 783=17\gdef\cloze#1{\colorbox{none}{\color{transparent}{\large{$\displaystyle #1$}}}} 7 - 8 \cdot 3 = \cloze{-17}

    abcabcabcd\gdef\cloze#1{\colorbox{none}{\color{transparent}{\large{$\displaystyle #1$}}}} a - b \cdot c \\ a \cdot b - c \\ a \cdot b - c \cdot d

    4
    Berechne!
    • 7149=119\gdef\cloze#1{\colorbox{none}{\color{transparent}{\large{$\displaystyle #1$}}}} 7 - 14 \cdot 9 = \cloze{-119}
    • 5174=81\gdef\cloze#1{\colorbox{none}{\color{transparent}{\large{$\displaystyle #1$}}}} 5 \cdot 17 - 4 = \cloze{81}
    • 615216=58\gdef\cloze#1{\colorbox{none}{\color{transparent}{\large{$\displaystyle #1$}}}} 6 \cdot 15 - 2 \cdot 16 = \cloze{58}
    • 3171019=139\gdef\cloze#1{\colorbox{none}{\color{transparent}{\large{$\displaystyle #1$}}}} 3 \cdot 17 - 10 \cdot 19 = \cloze{-139}
    • 816813=24\gdef\cloze#1{\colorbox{none}{\color{transparent}{\large{$\displaystyle #1$}}}} 8 \cdot 16 - 8 \cdot 13 = \cloze{24}
    • 318213=28\gdef\cloze#1{\colorbox{none}{\color{transparent}{\large{$\displaystyle #1$}}}} 3 \cdot 18 - 2 \cdot 13 = \cloze{28}
    • 7186=101\gdef\cloze#1{\colorbox{none}{\color{transparent}{\large{$\displaystyle #1$}}}} 7 - 18 \cdot 6 = \cloze{-101}
    • 317519=44\gdef\cloze#1{\colorbox{none}{\color{transparent}{\large{$\displaystyle #1$}}}} 3 \cdot 17 - 5 \cdot 19 = \cloze{-44}
    5
    Berechne!
    • 316210=28\gdef\cloze#1{\colorbox{none}{\color{transparent}{\large{$\displaystyle #1$}}}} 3 \cdot 16 - 2 \cdot 10 = \cloze{28}
    • 5144=51\gdef\cloze#1{\colorbox{none}{\color{transparent}{\large{$\displaystyle #1$}}}} 5 - 14 \cdot 4 = \cloze{-51}
    • 96+7=61\gdef\cloze#1{\colorbox{none}{\color{transparent}{\large{$\displaystyle #1$}}}} 9 \cdot 6 + 7 = \cloze{61}
    • 4148=108\gdef\cloze#1{\colorbox{none}{\color{transparent}{\large{$\displaystyle #1$}}}} 4 - 14 \cdot 8 = \cloze{-108}
    • 10114=34\gdef\cloze#1{\colorbox{none}{\color{transparent}{\large{$\displaystyle #1$}}}} 10 - 11 \cdot 4 = \cloze{-34}
    • 5106=44\gdef\cloze#1{\colorbox{none}{\color{transparent}{\large{$\displaystyle #1$}}}} 5 \cdot 10 - 6 = \cloze{44}
    • 7+57=42\gdef\cloze#1{\colorbox{none}{\color{transparent}{\large{$\displaystyle #1$}}}} 7 + 5 \cdot 7 = \cloze{42}
    • 5+97=68\gdef\cloze#1{\colorbox{none}{\color{transparent}{\large{$\displaystyle #1$}}}} 5 + 9 \cdot 7 = \cloze{68}
    • 2115=53\gdef\cloze#1{\colorbox{none}{\color{transparent}{\large{$\displaystyle #1$}}}} 2 - 11 \cdot 5 = \cloze{-53}
    • 71329=73\gdef\cloze#1{\colorbox{none}{\color{transparent}{\large{$\displaystyle #1$}}}} 7 \cdot 13 - 2 \cdot 9 = \cloze{73}
    • 8192=30\gdef\cloze#1{\colorbox{none}{\color{transparent}{\large{$\displaystyle #1$}}}} 8 - 19 \cdot 2 = \cloze{-30}
    • 313+107=109\gdef\cloze#1{\colorbox{none}{\color{transparent}{\large{$\displaystyle #1$}}}} 3 \cdot 13 + 10 \cdot 7 = \cloze{109}

    Mischung der Aufgaben

    1-4

  • Klammern zuerst

    1
    Berechne!
    • (4+7)8=88\gdef\cloze#1{\colorbox{none}{\color{transparent}{\large{$\displaystyle #1$}}}} (4 + 7) \cdot 8 = \cloze{88}
    • (4+8)(2+2)=48\gdef\cloze#1{\colorbox{none}{\color{transparent}{\large{$\displaystyle #1$}}}} (4 + 8) \cdot (2 + 2) = \cloze{48}
    • 7(7+7)=98\gdef\cloze#1{\colorbox{none}{\color{transparent}{\large{$\displaystyle #1$}}}} 7 \cdot (7 + 7) = \cloze{98}
    • (3+3)5=30\gdef\cloze#1{\colorbox{none}{\color{transparent}{\large{$\displaystyle #1$}}}} (3 + 3) \cdot 5 = \cloze{30}

    a(b+c)(a+b)c(a+b)(c+d)\gdef\cloze#1{\colorbox{none}{\color{transparent}{\large{$\displaystyle #1$}}}} a \cdot (b+c) \\ (a+b) \cdot c \\ (a+b) \cdot (c+d)

    2
    Berechne!
    • (77)13=0\gdef\cloze#1{\colorbox{none}{\color{transparent}{\large{$\displaystyle #1$}}}} (7 - 7) \cdot 13 = \cloze{0}
    • (134)(43)=9\gdef\cloze#1{\colorbox{none}{\color{transparent}{\large{$\displaystyle #1$}}}} (13 - 4) \cdot (4 - 3) = \cloze{9}
    • 8(311)=64\gdef\cloze#1{\colorbox{none}{\color{transparent}{\large{$\displaystyle #1$}}}} 8 \cdot (3 - 11) = \cloze{-64}
    • 4(1210)=8\gdef\cloze#1{\colorbox{none}{\color{transparent}{\large{$\displaystyle #1$}}}} 4 \cdot (12 - 10) = \cloze{8}

    a(bc)(ab)c(ab)(cd)\gdef\cloze#1{\colorbox{none}{\color{transparent}{\large{$\displaystyle #1$}}}} a \cdot (b-c) \\ (a-b) \cdot c \\ (a-b) \cdot (c-d)

    3
    Berechne!
    • (7+3)(151)=140\gdef\cloze#1{\colorbox{none}{\color{transparent}{\large{$\displaystyle #1$}}}} (7 + 3) \cdot (15 - 1) = \cloze{140}
    • (121)(119)=22\gdef\cloze#1{\colorbox{none}{\color{transparent}{\large{$\displaystyle #1$}}}} (12 - 1) \cdot (11 - 9) = \cloze{22}
    • (92)(144)=70\gdef\cloze#1{\colorbox{none}{\color{transparent}{\large{$\displaystyle #1$}}}} (9 - 2) \cdot (14 - 4) = \cloze{70}
    • (36)(12+4)=48\gdef\cloze#1{\colorbox{none}{\color{transparent}{\large{$\displaystyle #1$}}}} (3 - 6) \cdot (12 + 4) = \cloze{-48}

    "Klammer mal Klammer" in vier möglichen Varianten

    4
    Berechne!
    • 2+7(7+3)=72\gdef\cloze#1{\colorbox{none}{\color{transparent}{\large{$\displaystyle #1$}}}} 2 + 7 \cdot (7 + 3) = \cloze{72}
    • 4(6+1)+5=33\gdef\cloze#1{\colorbox{none}{\color{transparent}{\large{$\displaystyle #1$}}}} 4 \cdot (6 + 1) + 5 = \cloze{33}
    • 4+(4+4)4=36\gdef\cloze#1{\colorbox{none}{\color{transparent}{\large{$\displaystyle #1$}}}} 4 + (4 + 4) \cdot 4 = \cloze{36}
    • 8+9(3+10)=125\gdef\cloze#1{\colorbox{none}{\color{transparent}{\large{$\displaystyle #1$}}}} 8 + 9 \cdot (3 + 10) = \cloze{125}

    (a+b)c+d\gdef\cloze#1{\colorbox{none}{\color{transparent}{\large{$\displaystyle #1$}}}} (a+b) \cdot c +d
    in vier verschiedenen Anordnungen

    5
    Berechne!
    • 4+1(59)=0\gdef\cloze#1{\colorbox{none}{\color{transparent}{\large{$\displaystyle #1$}}}} 4 + 1 \cdot (5 - 9) = \cloze{0}
    • 6(82)+3=39\gdef\cloze#1{\colorbox{none}{\color{transparent}{\large{$\displaystyle #1$}}}} 6 \cdot (8 - 2) + 3 = \cloze{39}
    • (103)8+5=61\gdef\cloze#1{\colorbox{none}{\color{transparent}{\large{$\displaystyle #1$}}}} (10 - 3) \cdot 8 + 5 = \cloze{61}
    • 4+9(45)=5\gdef\cloze#1{\colorbox{none}{\color{transparent}{\large{$\displaystyle #1$}}}} 4 + 9 \cdot (4 - 5) = \cloze{-5}

    (ab)c+d\gdef\cloze#1{\colorbox{none}{\color{transparent}{\large{$\displaystyle #1$}}}} (a-b) \cdot c +d
    in vier verschiedenen Anordnungen

  • 6
    Berechne!
    • (7+4)47=37\gdef\cloze#1{\colorbox{none}{\color{transparent}{\large{$\displaystyle #1$}}}} (7 + 4) \cdot 4 - 7 = \cloze{37}
    • 22(3+2)=8\gdef\cloze#1{\colorbox{none}{\color{transparent}{\large{$\displaystyle #1$}}}} 2 - 2 \cdot (3 + 2) = \cloze{-8}
    • (6+7)44=48\gdef\cloze#1{\colorbox{none}{\color{transparent}{\large{$\displaystyle #1$}}}} (6 + 7) \cdot 4 - 4 = \cloze{48}
    • 2(5+3)2=14\gdef\cloze#1{\colorbox{none}{\color{transparent}{\large{$\displaystyle #1$}}}} 2 \cdot (5 + 3) - 2 = \cloze{14}

    (a+b)cdbzw.d(a+b)c\gdef\cloze#1{\colorbox{none}{\color{transparent}{\large{$\displaystyle #1$}}}} (a+b) \cdot c - d \\ \text{bzw.} \\ d - (a+b) \cdot c

    7
    Berechne!
    • 33(74)=6\gdef\cloze#1{\colorbox{none}{\color{transparent}{\large{$\displaystyle #1$}}}} 3 - 3 \cdot (7 - 4) = \cloze{-6}
    • 510(65)=5\gdef\cloze#1{\colorbox{none}{\color{transparent}{\large{$\displaystyle #1$}}}} 5 - 10 \cdot (6 - 5) = \cloze{-5}
    • (45)46=10\gdef\cloze#1{\colorbox{none}{\color{transparent}{\large{$\displaystyle #1$}}}} (4 - 5) \cdot 4 - 6 = \cloze{-10}
    • 5(38)8=45\gdef\cloze#1{\colorbox{none}{\color{transparent}{\large{$\displaystyle #1$}}}} 5 - (3 - 8) \cdot 8 = \cloze{45}

    (ab)cdbzw.d(ab)c\gdef\cloze#1{\colorbox{none}{\color{transparent}{\large{$\displaystyle #1$}}}} (a-b) \cdot c - d \\ \text{bzw.} \\ d - (a-b) \cdot c

    Es sind natürlich noch zahlreiche weitere Varianten dieser Aufgaben möglich - der Kreativität sind hier keine Grenzen gesetzt!